x^2+14*x=100

Solution for x^2+14*x=100 equation:

x^2+14x=100

We move all terms to the left:

x^2+14x-(100)=0

a = 1; b = 14; c = -100;
Δ = b2-4ac
Δ = 142-4·1·(-100)
Δ = 596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{596}=\sqrt{4*149}=\sqrt{4}*\sqrt{149}=2\sqrt{149}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{149}}{2*1}=\frac{-14-2\sqrt{149}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{149}}{2*1}=\frac{-14+2\sqrt{149}}{2}
$